-5y^2+26y+24=0

Solution for -5y^2+26y+24=0 equation:

-5y^2+26y+24=0

a = -5; b = 26; c = +24;
Δ = b2-4ac
Δ = 262-4·(-5)·24
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-34}{2*-5}=\frac{-60}{-10}
=+6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+34}{2*-5}=\frac{8}{-10}
=-4/5
$